Help:How can I create hierarchies of categories?


 * Question
 * question:=How can I create hierarchies of categories?


 * Answer
 * description:=Use "Annotate" or "Sub/Super" in the "Categories" tool box while you are editing a category.



Prerequisites

You are editing an article that defines a category.

Goal 1

You want to make this category a sub-category of other categories.

Workflow 1

Click "Annotate" in the "Categories" section of the semantic toolbar.

Enter the name of the super category in the field "Name". Auto-completion supports you. In addition the system checks, if the category already exists when you stop typing. Green signals an existing category and orange a non-existing.

In any case, you can press the "Add"-button. The new annotation is appended at the end of the article and the current category has become its sub-category.

Goal 2

You want to make this category a sub-category of another category. If the super-category does not exist, it is created.

Workflow 2

You edit a category page: Press "Sub/Super" in the "Categories" section of the semantic toolbar. An input field for the name of the super category appears.



Enter the name of the super category (supported by auto-completion) and press Enter or Tab. The system checks, if the category already exist and signals this with green (exists) or orange (does not exist), respectively.



Anyway, click "Create ... super category..." or "Make ... super category ...". The current article is annotated as sub-category. If the super category does not exist, it is created and opened in a new browser tab. (Popup-blockers might prevent this, but can be configured to allow it.)

Goal 3

You want to make this category a super-category of another category. If this sub-category does not exist, it is created.

Workflow 3

The workflow is the same as in Workflow 2, with the exception that you click "Make ... sub category... " or "Create ... sub category... ". The current article is not changed and the (possibly new) category is annotated as sub-category.